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5z^2-54z-11=0
a = 5; b = -54; c = -11;
Δ = b2-4ac
Δ = -542-4·5·(-11)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-56}{2*5}=\frac{-2}{10} =-1/5 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+56}{2*5}=\frac{110}{10} =11 $
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